题目链接 BZOJ
当然哪都能交(都比在BZOJ交好)，比如UOJ #58

//67376kb   27280ms
//树上莫队+带修改莫队 模板题 
#include <cmath>
#include <cstdio>
#include <cctype>
#include <cstring>
#include <algorithm>
//#define gc() getchar()
#define MAXIN 400000
#define gc() (SS==TT&&(TT=(SS=IN)+fread(IN,1,MAXIN,stdin),SS==TT)?EOF:*SS++)
typedef long long LL;
const int N=1e5+5,M=1e6+3;int n,m,Enum,H[N],nxt[N<<1],to[N<<1],val[M],W[N],col[N],las[N],tm[M];
int fa[N],dep[N],sz[N],son[N],top[N],Index,in[N],out[N],seq[N<<1];
LL Now,Ans[M];
bool vis[N];
char IN[MAXIN],*SS=IN,*TT=IN;
struct Queries
{int l,r,lca,bl,br,tm,id;bool operator <(const Queries &x)const{if(bl!=x.bl) return bl<x.bl;//能优化15%？if(br!=x.br) return bl&1?br<x.br:br>x.br;return (bl^br)&1?tm<x.tm:tm>x.tm;
//      if(bl==x.bl) return br==x.br?tm<x.tm:br<x.br;
//      return bl<x.bl;}
}q[M];
struct Modify
{int pos,val,bef;
}qm[M];inline int read()
{int now=0;register char c=gc();for(;!isdigit(c);c=gc());for(;isdigit(c);now=now*10+c-'0',c=gc());return now;
}
inline void AddEdge(int u,int v)
{to[++Enum]=v, nxt[Enum]=H[u], H[u]=Enum;to[++Enum]=u, nxt[Enum]=H[v], H[v]=Enum;
}
inline int LCA(int u,int v)
{while(top[u]!=top[v]) dep[top[u]]>dep[top[v]]?u=fa[top[u]]:v=fa[top[v]];return dep[u]>dep[v]?v:u;
}
void DFS1(int x)
{int mx=0; sz[x]=1;for(int v,i=H[x]; i; i=nxt[i])if((v=to[i])!=fa[x]){fa[v]=x, dep[v]=dep[x]+1, DFS1(v), sz[x]+=sz[v];if(mx<sz[v]) mx=sz[v], son[x]=v;}
}
void DFS2(int x,int tp)
{seq[in[x]=++Index]=x, top[x]=tp;if(son[x]){DFS2(son[x],tp);for(int i=H[x]; i; i=nxt[i])if(to[i]!=fa[x]&&to[i]!=son[x]) DFS2(to[i],to[i]);}seq[out[x]=++Index]=x;
}
void Calc(int p)
{vis[p] ? Now-=1ll*W[tm[col[p]]--]*val[col[p]] : Now+=1ll*W[++tm[col[p]]]*val[col[p]];vis[p]^=1;
}
void Change(int p,int v)
{if(vis[p]) Calc(p), col[p]=v, Calc(p);else col[p]=v;
}int main()
{n=read(), m=read(); int Q=read();for(int i=1; i<=m; ++i) val[i]=read();for(int i=1; i<=n; ++i) W[i]=read();for(int i=1; i<n; ++i) AddEdge(read(),read());for(int i=1; i<=n; ++i) col[i]=las[i]=read();DFS1(1), DFS2(1,1);int qcnt=0, mcnt=0, size=pow(n,2.0/3.0);for(int i=1,x,y,w; i<=Q; ++i)if(!read()) qm[++mcnt]=(Modify){x=read(),y=read(),las[x]},las[x]=y;else{x=read(), y=read();
//          if(x==y) {q[++qcnt].lca=-1, Ans[qcnt]=...; continue;}w=LCA(x,y);if(in[x]>in[y]) std::swap(x,y);if(x==w) q[++qcnt]=(Queries){in[x],in[y],0,in[x]/size,in[y]/size,mcnt,qcnt};else q[++qcnt]=(Queries){out[x],in[y],w/*in[w]*/,out[x]/size,in[y]/size,mcnt,qcnt};}std::sort(q+1,q+1+qcnt);for(int i=1,t=0,l=1,r=0,ql,qr,qt; i<=qcnt; ++i){ql=q[i].l, qr=q[i].r, qt=q[i].tm;while(t<qt) ++t,Change(qm[t].pos,qm[t].val);while(t>qt) Change(qm[t].pos,qm[t].bef),--t;if(ql==qr) {Ans[q[i].id]=1ll*val[col[seq[q[i].l]]]*W[1]; continue;}while(l<ql) Calc(seq[l++]);while(l>ql) Calc(seq[--l]);while(r<qr) Calc(seq[++r]);while(r>qr) Calc(seq[r--]);if(q[i].lca) Calc(q[i].lca);//Calc(seq[in[lca]]) = Calc(lca)Ans[q[i].id]=Now;if(q[i].lca) Calc(q[i].lca);}for(int i=1; i<=qcnt; ++i) printf("%lld\n",Ans[i]);return 0;
}

转载于:https://www.cnblogs.com/SovietPower/p/9383233.html